Two blocks of mass 2 kg and 4 kg are connected through a massless inextensible string. Coefficient of friction between 2 kg block and ground is 0.4 and between 4 kg block and ground is 0.6. Two forces F 1 = 10 N and F 2 = 20 N are applied on the block as shown in figure. Friction force (in N) acting on 4 kg block minus 10 N is
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
( 18)
Sol. For equilibrium,
10 = 8 + T …(i)
T + f 2 = 20 …(ii)
f 2 = 18N
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